The domain of a function is the set of all values that can be plugged into a function and have the function defined. Besides that, the function has a real number for a value. Given the function f(x) = 3x + 5.Subscribe for new videos: www.youtube.com/channel/UCIWCSw8jNs9SPetsVPo1WQQShare this video: https://youtu.be/qpnJcI6XuQMThe problem: Make a function table fo...What are the domain and range of f(x) = 2(3x)? Answers: 1 Get : ) Other questions on the subject: Mathematics. Mathematics, 24.06.2019 09:00,Transcript. Example 21 Find the domain of the function "f" (x) = (" " 2 + 3 + 5)/( 2 5 + 4) "f" (x) = (" " x2 + 3x + 5)/(x2 5x + 4) = (x2 + 3x + 5)/(x2 4x + 4) = (x2 + 3x +5)/( (x 4) 1( 4)) = (x2 + 3x + 5)/(( 4)(x 1) ) In real numbers , the denominator cannot be zero Hence (x 4) (x 1) 0 x 4 and x 1 Hence the domain of the function will be all real numbers except 1 and 4 Hence, the domain = RHow do you find the domain and range of # f(x)=2/(3x-1)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function. 1 Answer Narad T. May 26, 2018 The domain is #x in (-oo, 1/3) uu(1/3,+oo)#. The range is #y in (-oo,0) uu(0,+oo)# Explanation: The denominator must be #!=0# Therefore,
How to Make a Function Table for f(x)=-3x+7 (then state
Even though they are represented differently, the above are the same function, and the domain of the function is x = {2, 3, 5, 6, 8} and the range is y = {4, 8, 2, 9, 3}. This is how you can defined the domain and range for discrete functions. The order in which you list the values does not matter.f(x) = 3x + 5 => y = 3x + 5, here it is a straight line increasing with slope 3 and y-intercept 5,so both domain and range of the given function is all real number (-∞,∞) 13 views Related AnswerTranscript. Ex 2.3, 5 Find the range of each of the following functions. f(x) = 2 - 3x, x ∈ R, x > 0. Given that x > 0, Multiplying 3 both sides 3x > 0 × 3 3x > 0 Multiplying -1 both sides - 1 × 3x < - 1 × 0 - 3x < 0 Adding 2 both sides 2 - 3x < 2 + 0 (We need to make it in form 2 - 3x) 2 - 3x < 2 f(x) < 2 We note that value of f(x) is less than 2 (not including 2) HenceThe domain of the function is all of the x-values (horizontal axis) that will give you a valid y-value output. The function equation may be quadratic, a fraction, or contain roots. To calculate the domain of the function, you must first evaluate the terms within the equation. A quadratic function has the form ax 2 + bx + c: f (x) = 2x 2 + 3x + 4
What are the domain and range of f(x) = 2(3x)?
Include: - Domain and range - Period - Two Vertical Asymptotes Algebra -> Rational-functions -> SOLUTION: Analyze the function f(x) = - 2 cot 3x. Algebra: Rational Functions, analyzing and graphing SectionPrecalculus Find the Domain and Range f(x)=x^3-3x+2 The domainof the expressionis all real numbers except where the expressionis undefined. In this case, there is no real number that makes the expressionundefined.f(x)=(2x+3/4)^2-25/16. Domain: x is real. Range: f(x)>=-25/16 (If you include complex numbers, both domains are C) Comment on Fuqar's solution: Range includes negative values for f(x) because f(0)=-1As we have g(x) = 3x+2 Domain :- for the value of x, g(x) € R. Domain:- (−∞,∞),{x|x∈R}. Then Domain of g(x) = R, for all x € R # for range, let g(x) = yWhat are the domain and range of the real-valued function f(x)=2/3x? A. The domain is all real number except 0. The range is all real numbers except 0. B. The domain and the range are all real numbers. C. The domain is x>0. The range is f(x)>0. D. The domain is all real numbers except 0. The range is all real numbers
Option A. Domain = (-Infinity, Infinity); Range (0, Infinity)
Solution:
f(x)=2^(3x)
a) This is an exponential function, and we should not have restrictions for the independent variable "x" in the exponent, then the Domain of f(x) is all the actual numbers:
Domain f(x) = ( - Infinity, Infinity)
b) To to find the range we will find the inverse function f^(-1) (x). The domain of the inverse function is the range of the unique function f(x):
y=f(x)
y=2^(3x)
Isolating x: Applying log either side of the equation:
log y = log 2^(3x)
Applying assets of logarithm: log a^b = b log a; with a=2 and b=3x
log y = 3x log 2
Dividing each side by means of 3 log 2:
log y / (three log 2)=3x log 2 / (three log 2)
log y / (three log 2)=x
x=log y / (three log 2)
Changing x by way of f^(-1) (x) and y by x:
f^(-1) (x) = log x / (three log 2)
This is a logaritmic function and the argument of the logarithm should be greater than zero, then the Domain of the inverse function is:
x>0→Domain f^(-1) (x) = (0, Infinity)
The domain of the inverse is the range of the unique function:
Range f(x) = Domain f^(-1) (x)
Range f(x) = (0, Infinity)
Domain f(x) = ( - Infinity, Infinity)
Range f(x) = ( 0, Infinity)
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